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Hi Everybody, My first post here and i was wondering if anybody has had experience with using a transit and grade rod to figure up a road bore. If so, how do you do it and what is the formula you use? Thank you
Using a transit to figure out a road bore
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I didn't go to college
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I'm very well familiar with the grade rod and understand it well, but i do not know what equation i would use to figure out what degree the road will need to be bored at. So my question is after i gather up my shots, what formula is used to figure out the degree from transit shots
http://www.calculator.net/triangle-...=4&vy=60&va=90&vz=&vb=&angleunits=d&x=94&y=10
Need to know the rise (difference in height)
Run (length of bore)
Use 90 degrees as a given angle.
Sent from my SM-G930V using Tapatalk
Need to know the rise (difference in height)
Run (length of bore)
Use 90 degrees as a given angle.
Sent from my SM-G930V using Tapatalk
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Difference in height as in the entry hole and the exit hole?
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Mike B new exactly what I was asking. Just trying to figure out if the rise is figured out by your entry shot and your exit shot
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Rise and run are very basic equations, but using the right numbers is what I'm asking.
Are you attempting to convert your total rise in feet/tenths, to degree of slope?
Delta
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My rise is already figured in tenths due to my grade rod. Just wanting to know what number to use for the equation. I'm pretty sure it's my transit shot at the entry of the bore hole and the exit of the bore hole
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For rise over run
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Preferably someone who has shot road bores before, nobody has really narrowed it down for me except Mike B im pretty sure I have to use tangent inverse. Mike B has seemed like he's understood my question the best. Would really like to hear from him again
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That is the description of the Pythagorean Theorem.
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Never mind guys I finally figured it out, it's tangent inverse of the rise over run answer that gives you the degree your bore pipe needs to be looking at the point of entry
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Difference of the two elevations over the distance in feet between the shots, point of entry - point of exit , say a 4 rod right of way, of 66 feet with an elevation of 963.34 feet entry going up hill to 965.67 feet is a difference of +(slopes upward!) 2.33 feet over 66' = 0.035303/1.00 grade, a big+3.5 % grade UPWARDs from the low shot.
Doesn't the machine come with hours of U-tube training videos?
A couple of days training much cheaper than fixing a 10,000 pair fiber optic line...etc...
If your post comes into evidence after you torpedo a fiber cable, good luck getting insured and a new job....:thumbsup:
Doesn't the machine come with hours of U-tube training videos?
A couple of days training much cheaper than fixing a 10,000 pair fiber optic line...etc...
If your post comes into evidence after you torpedo a fiber cable, good luck getting insured and a new job....:thumbsup:
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