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I am looking to build a deck over a retention area on one of my company's properties- will be a smoking area. In order to save a few bucks I get to be the engineer on this one. The retention area is 22'8" by 90+' and 5' deep and constructed of 8-8-16 CMU dowelled with #5 and poured solid. I need to span the 22'8 with a 30' wide deck, ideally attaching ledgers to the CMU walls on 2 sides. Span tables say I can go 22'8" with 2x12 #1 SYP at 12"OC, but the lumber yards say no #1 that long. Second idea was a treated PSL spanning 30' at the midpoint on the 22'6 and hanging joists, but treated PSL sized for that application was $42+ per foot (over $1300) plus the footings, posts, and hardware to hold it up. Next idea would be a built up beam in place of the PSL, but I could use some advice for calculating the size and assembly. Deck is 22.66x30=680s.f.. Code says 40/10 loading so 680*50=34000 lbs total loading. Divide by 3 gives me center beam load of 11,333. My joist span being under 11 now, I determine that I need 2x8 #2 joists at 16"OC. My 30' beam divided by 23 joists gives me just under 500 lbs every 16" as an evenly distributed load.
Now for the question. Assuming all of the above calcs are correct (think so, but will humbly accept any corrections), how big of a built up beam do I need (size and composition), how many piligs supporting it, how big should the pilings be, and how do you arrive at this answer?
Now for the question. Assuming all of the above calcs are correct (think so, but will humbly accept any corrections), how big of a built up beam do I need (size and composition), how many piligs supporting it, how big should the pilings be, and how do you arrive at this answer?