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Old 10-24-2007, 09:52 PM   #1
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Math


I have a question if you have 36kva at 230 volts 3 phase what is the math formula to get the amperage per leg. I know it has 1.73 in it but can't for the life of me remember it. If you could help that would be great.

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Old 10-24-2007, 09:54 PM   #2
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Re: Math


36000/230*1.73
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Old 10-24-2007, 09:57 PM   #3
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Re: Math


VA/ Volts x 1.73

36,000 VA divided by 230 volts x 1.73

Answer is 271 amps per leg.

Last edited by Magnettica; 10-24-2007 at 10:00 PM.
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Old 10-24-2007, 09:58 PM   #4
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Re: Math


Watts divided by volts divided by the square root of 3 (1.73).
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Old 10-24-2007, 10:04 PM   #5
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Re: Math


so 36000divided by 230 divided by 1.73 = 90 amps per leg correct?
wow thats alot of power for a cnc machine.
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Old 10-24-2007, 10:16 PM   #6
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Re: Math


Not for a big one.

Another way is: watts / (voltsx1.73) as Joe and Mag wrote. Same result.

36000÷(230x1.73)
36000÷397=90.68

or

36000÷230÷1.73
156.52÷1.73=90.47
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Old 10-24-2007, 10:21 PM   #7
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Re: Math


http://www.angelfire.com/pa/baconbacon/page2.html


Some useful formulas for you.
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Old 10-24-2007, 10:23 PM   #8
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Re: Math


Quote:
Originally Posted by Magnettica View Post
VA/ Volts x 1.73

36,000 VA divided by 230 volts x 1.73

Answer is 271 amps per leg.
???

36,000/(1.73*230)=
36,000/398=
90.5A

How are you arriving at 271 per?
(90.5*3=271.5)
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Old 10-24-2007, 10:23 PM   #9
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Re: Math


The answer is on pages 57 and 58 of your Ugly's book.
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Old 10-24-2007, 10:41 PM   #10
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Re: Math


Quote:
Originally Posted by Celtic View Post
???

36,000/(1.73*230)=
36,000/398=
90.5A

How are you arriving at 271 per?
(90.5*3=271.5)

I blanked up.

I did 36kva/ 230 and took that sum and multiplied it by 1.73.

I see where I went wrong.
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Old 10-25-2007, 09:59 PM   #11
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Re: Math


Quote:
Originally Posted by Magnettica View Post
I blanked up.

I did 36kva/ 230 and took that sum and multiplied it by 1.73.

I see where I went wrong.

Hmmm, that would have made a big difference in the price of the wire.........
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Old 10-25-2007, 11:13 PM   #12
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Re: Math


I believe that secondary windin configuration has something to do with the calc. (Wye or Delta).
Without vast knowledge I think Mag could also be right, given the configuration wasn't given in the question?

Last edited by Sparky Joe; 10-25-2007 at 11:15 PM.
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Old 10-26-2007, 06:27 PM   #13
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Re: Math


Mistakenly, I gave total amperage of all 3 legs, not amps per leg.

270/ 3 = 90
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Old 10-26-2007, 06:32 PM   #14
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Re: Math


Quote:
Originally Posted by Magnettica View Post
Mistakenly, I gave total amperage of all 3 legs, not amps per leg.

270/ 3 = 90
??

HUH?

A 3Ø load with 90A per leg needs a 300A CB ('cause there is NO 270A CB)?
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Old 10-26-2007, 06:42 PM   #15
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Re: Math


I thought we were talking about amperage per leg?

Yes, a 300A breaker would be correct protecting a 270 amp load.

240.4 (B)
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Old 10-26-2007, 06:50 PM   #16
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Re: Math


Quote:
Originally Posted by Magnettica View Post
I thought we were talking about amperage per leg?
We are.....how did you arrive at this...
Quote:
Originally Posted by Magnettica View Post
Mistakenly, I gave total amperage of all 3 legs, ....
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Old 10-26-2007, 06:55 PM   #17
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Re: Math


Because at 90 amps per leg

a = 90 amps
b= 90 amps
c = 90 amps

90 + 90 + 90 = 270

Are u messing with me?
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Old 10-26-2007, 08:09 PM   #18
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Re: Math


Quote:
Originally Posted by Magnettica View Post
Are u messing with me?
No...
I'm trying to figure out how we went from this...
Quote:
Originally Posted by sckeeth View Post
I have a question if you have 36kva at 230 volts 3 phase what is the math formula to get the amperage per leg.
...to this...

Quote:
Originally Posted by Magnettica View Post
Because at 90 amps per leg

a = 90 amps
b= 90 amps
c = 90 amps

90 + 90 + 90 = 270
Where/when does the 270A ever become useful information?


I realize you had a brain-fart on the math previously...but what's with the 270A ?
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Old 10-26-2007, 09:05 PM   #19
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Re: Math


You guys are giving me a headache.
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Old 10-27-2007, 01:29 AM   #20
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Re: Math


The 270 comes from 36kva divided by 230 times 1.73.

270 divided by 3 is 90.

270 is the result of a incorrect math figure that mathmatically works out to be the sum of all three legs.

It's just something I picked up on after I realized where
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